Ask Question
31 July, 01:33

The volume of a cantaloupe is approximated by Upper V equals four thirds pi font size decreased by 5 r cubed. The radius is growing at the rate of 0.5 cm divided by week , at a time when the radius is 6.4 cm. How fast is the volume changing at that moment?

+3
Answers (1)
  1. 31 July, 04:41
    0
    308.67 cm ^ 3 / week

    Step-by-step explanation:

    A cantaloupe is approximately a sphere, therefore its approximate volume would be:

    V = (4/3) * pi * (r ^ 3)

    They tell us that dr / dt 0.5 cm / week and the radius is 6.4 cm

    if we derive the formula from the volume we are left with:

    dV / dt = (4/3) * pi * d / dr [ (r ^ 3) ]

    dV / dt = (4/3) * pi * 3 * (r ^ 2) * dr / dt

    dV / dt = 4 * pi * (r ^ 2) * dr / dt

    we replace all the values and we are left with:

    dV / dt = 4 * 3.14 * (6.4 ^ 2) * 0.6

    dV / dt = 308.67

    Therefore the volume is changing at a rate of 308.67 cm ^ 3 / week
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The volume of a cantaloupe is approximated by Upper V equals four thirds pi font size decreased by 5 r cubed. The radius is growing at the ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers