FInd three consecutive even integers such that three times the smallest is four more than twice the largest

n, n + 2, n + 4 - three consecutive even integers

3n = 2 (n + 4) + 4 |use distributive property

3n = (2) (n) + (2) (4) + 4

3n = 2n + 8 + 4

3n = 2n + 12 |subtract 2n from both sides

n = 12

n + 2 = 12 + 2 = 14

n + 4 = 12 + 4 = 16

Answer: 12, 14, 16.