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27 January, 23:37

If one zero of the polynomial (a^2+9) x^2+13x+6a is the reciprocal of the other, find the value of a.

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  1. 28 January, 01:20
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    Answer: a^2x^2+9x^2+13x+6a

    Step-by-step explanation:

    (a^2+9) x^2 + 13x + 6a

    x^2 (a^2+9) + 13x+6a

    Expand:x^2 (a^2+9) : a^2 x^2+9^2

    x^2 a^2 + x^2*9

    a^2 x^2+9x^2

    a^2 x^2+9x^2+13x+6a
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