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16 November, 05:17

What is the solution to logs (10x-1) = logs (9x + 7) ?

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  1. 16 November, 07:59
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    x=8

    Step-by-step explanation:

    log (10x-1) = log (9x + 7)

    Since both logs are to the same base, the insides must be the same

    10x-1 = 9x+7

    Subtract 9x from each side

    10x - 9x-1 = 9x-9x+7

    x-1 = 7

    Add 1 to each side

    x-1+1=7+1

    x=8
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