Ask Question
MathematicsMathematics
24 October, 17:43

TriangleABC has three sides with these lengths: AB=9, BC=40, and CA=41, What is the value of cos C?

+5
Answers (1)
  1. 24 October, 21:08
    0
    9² = 40² + 41² - 2 (40) (41) cos (C)

    81 = 1600 + 1681 - 3280 cos (C)

    81 = 3281 - 3280 cos (C)

    -3200 = - 3280 cos (C)

    cos (C) = 3200 / 3280

    cos (C) = 40 / 41
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “TriangleABC has three sides with these lengths: AB=9, BC=40, and CA=41, What is the value of cos C? ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers
You Might be Interested in
Measure of angle 7 = 2x+15 measure of angle 8 = 3x
Answers (2)
Which fraction is equivalent to 1/3
Answers (2)
Write expressions for 4 consecuative integers. Evaluate the expressions when the first integer is 33.
Answers (1)
Charlotte bought packs of hot dogs for $4 each. Eack pack has 8 hot dogs. If she spent $16 how many hot dogs did she get
Answers (2)
What is the value of x in the question 2 (x-4) = 4 (2x+1)
Answers (1)
New Questions in Mathematics
5 - 11t = 7 (5 - 2t)
Answers (1)
A student concluded that the solution to the equation 2x+1+3=0 isr=4 Do you agree? Explain why or why not.
Answers (1)
How to solve 8,725+w=10,619
Answers (2)
Como se lee éste numero: 0,08
Answers (1)
How do you find the sum of all integers between square root of 12 + square root of 40?
Answers (1)
Home » Mathematics » TriangleABC has three sides with these lengths: AB=9, BC=40, and CA=41, What is the value of cos C?
Sign Up Forgot Password?