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9 April, 00:44

Last year Oscar bought a packet of biscuits every week and found 30 of 3 these packets contained broken biscuits. What is the relative frequency

of this event? Answer correct to 2 decimal places. Explain why you

chose the numbers in your calculation

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Answers (1)
  1. 9 April, 02:30
    0
    Relative Frequency = 0.58

    Step-by-step explanation:

    Given

    A packet of biscuit every week

    Number of packets that contains broken biscuits = 30

    Required

    Relative Frequency

    First, the total packet of biscuit bought needs to be calculated.

    The question says Oscar bought a packet every week of the year and there are 52 weeks in a year.

    This means that Oscar bought 52 packets of biscuits.

    So, we can conclude that 30 out 52 packets contains broken biscuits.

    The relative frequency is then calculated as this;

    Relative Frequency = Number of packets that contains broken biscuits divided by total number of packets.

    Relative Frequency = 30/52

    Relative Frequency = 0.5769230769

    Relative Frequency = 0.58 (Approximated).

    Hence, the relative frequency of the broken packets of biscuits is 0.58
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