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25 April, 12:17

The area of each triangular base is: A = 1/2 (b) (h) A = 1/2 (4) (3) A = in. 2 There are two bases, so total base area is in. 2. The lateral area is: A = 8 (4) + 8 (3) + 8 (5) A = in. 2 The total surface area is in. 2.

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  1. 25 April, 12:27
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    6 in^2

    12 in^2

    96 in^2

    AT = 108 in^2

    Step-by-step explanation:

    The area of one triangular face is

    A1 = 1/2 (4) (3) = 6 in^2

    The area of the two triangular faces is:

    A = 2A1 = 12 in^2

    the area of the lateral faces is:

    Al = 8 (4) + 8 (3) + 8 (5) = 96 in^2

    Hence, the total surface area is

    AT = At + Al = 12 in^2 + 96 in^2 = 108 in^2
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