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16 May, 10:04

Mr. Lee asks a student to solve the following system of linear equations. {-28=-40q-14p 10q+4=2p Which ordered pair (p, q) is a solution to the system? (-7/5,-2) (-2,-7/5) (0, 2) (2, 0)

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  1. 16 May, 11:21
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    p = 2, q = 0

    Step-by-step explanation:

    Solve the following system:

    {-28 = - 14 p - 40 q | (equation 1)

    10 q + 4 = 2 p | (equation 2)

    Express the system in standard form:

    {14 p + 40 q = 28 | (equation 1)

    - (2 p) + 10 q = - 4 | (equation 2)

    Add 1/7 * (equation 1) to equation 2:

    {14 p + 40 q = 28 | (equation 1)

    0 p + (110 q) / 7 = 0 | (equation 2)

    Divide equation 1 by 2:

    {7 p + 20 q = 14 | (equation 1)

    0 p + (110 q) / 7 = 0 | (equation 2)

    Multiply equation 2 by 7/110:

    {7 p + 20 q = 14 | (equation 1)

    0 p+q = 0 | (equation 2)

    Subtract 20 * (equation 2) from equation 1:

    {7 p+0 q = 14 | (equation 1)

    0 p+q = 0 | (equation 2)

    Divide equation 1 by 7:

    {p+0 q = 2 | (equation 1)

    0 p+q = 0 | (equation 2)

    Collect results:

    Answer: {p = 2, q = 0
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