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30 April, 03:40

A runner runs around a track consisting of two parallel lines 96 m long connected at the ends by two semicircles with a radius of 49 m. She completes one lap in 100 seconds. What is her average velocity?

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Answers (2)
  1. 30 April, 04:46
    0
    Answers:0m/s

    Step-by-step explanation: once she has completed one lap, displacement is 0, therefore her velocity is 0m/s
  2. 30 April, 07:09
    0
    5 m/s

    Step-by-step explanation:

    First task is to find the total length of the track.

    We know it's made out of 2 straight lines of 96 m long ... and 2 semicircles with a radius of 49 m.

    Since we have TWO semicircles, we can say we have one circle ... so we can calculate its circumference:

    C = 2 * π * r = 2 * 3.14 * 49 = 307.72 m

    This is for the both semicircles at the ends. Now, let's add the two 96 m long straight lines to get the full length of the track:

    T = 307.72 + 96 + 96 = 499.72 m

    Now that we have the total length of the track, we can easily calculate her average speed.

    She does one lap in 100 seconds, so her average speed/velocity is:

    S = 499.72 m / 100 s = 4.9972 m/s or 5 m/s if we round up a bit.
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