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Mathematics
Karma
16 December, 12:30
F (x) = x 2 + 6 and g (x) = 2x - 1
g[f (x) ] =
+4
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1
)
Lesly
16 December, 13:19
0
Given,
f (x) = x^2+6
g (x) = 2x-1
Now,
g[f (x) ]=g (x^2+6) since f (x) = x^2+6
=2 (x^2+6) - 1 since x > x^2+6
=2x^2+12-1
=2x^2+11
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