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28 October, 23:52

What is a counterexample of the following conjecture any number that is divisible by 3 is also divisible by 6

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  1. 29 October, 02:46
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    Any odd multiple of 3 would be the counterexample of the given conjecture.

    That is 3 (2n - 1), for any natural number n, will be divisible by 3 but not divisible by 6 as 2 is not a factor.

    Examples:

    3 (3) = 9

    3 (5) = 15

    3 (7) = 21 are some examples.
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