What is the general equation of a sine function with an amplitude of 2, a period of Pi and a horizontal shift of Pi units? y = 2 sine (2 (x minus pi)) y = 2 sine (4 (x + pi)) y = sine (0.5 (x minus pi)) y = sine (2 (x + pi))

The general equation of the sine function is;

y = 2 sine (2 (x - π))

Step-by-step explanation:

Mathematically, the general equation of a sine function (sinusoid) can be written as;

y = A sin (B (x-C)) + D

where, A represents the amplitude

B is the frequency, where period = 2 π/B

D is vertical shift

C is the horizontal or phase shift

From the question, we have the following;

Amplitude of 2 (A),

Period = π

Since Period = 2 π/B

This means that π = 2 π/B

Dividing both sides by π; B = 2

Horizontal shift = π units = C

Plugging these values, we have

y = 2 sine (2 (x - π))