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9 October, 12:05

How many solutions does x^2-8x + 16=0 have and which ones are they

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  1. 9 October, 15:18
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    2

    Step-by-step explanation:

    Given

    x² - 8x + 16 = 0

    Consider the factors of the constant term ( + 16) which sum to give the coefficient of the x - term ( - 8)

    The factors are - 4 and - 4, since

    - 4 * - 4 = + 16 and - 4 - 4 = - 8, thus

    (x - 4) (x - 4) = 0

    Equate each factor to zero and solve for x

    x - 4 = 0 ⇒ x = 4

    x - 4 = 0 ⇒ x = 4

    The solution is x = 4 with multiplicity 2
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