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Mathematics
Gunner Kane
7 September, 19:01
Solve the system.
0.4x - 0.1y = 2
0.2x + 0.5y = 1
+1
Answers (
1
)
Maddison Miles
7 September, 20:50
0
x = 5
y = 0
respectively
Step-by-step explanation:
in order to solve this system of equation we say that let
0.4x - 0.1y = 2 ... equation 1
0.2x + 0.5y = 1 ... equation 2
from equation 2
0.2x + 0.5y = 1 ... equation 2
0.2x = 1 - 0.5y
divide both sides by the coefficient of x which is 0.2
0.2x/0.2 = (1 - 0.5y) / 0.2
x = (1 - 0.5y) / 0.2 ... equation 3
substitute for equation 3 in equation 1
0.4x - 0.1y = 2 ... equation 1
0.4 (1 - 0.5y) / 0.2 - 0.1y = 2
0.4 - 0.2y/0.2 - 0.1y = 2
multiply through by 0.2
we have,
0.4 - 0.2y - 0.02y = 0.4
collect the like terms
0.4 - 0.4 = 0.2y + 0.02y
0 = 0.22y
divide both sides by the coefficient of y which is 0.22
0/0.22 = 0.22y/0.22
y = 0
put y = 0 into equation 3
x = (1 - 0.5y) / 0.2 ... equation 3
x = 1 - 0.5 (0) / 0.2
x = 1 - 0/0.2
x = 1/0.2
x = 5
therefore the value of x is 5 and y is 0 respectively
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