Solve the system.

0.4x - 0.1y = 2

0.2x + 0.5y = 1

x = 5

y = 0

respectively

Step-by-step explanation:

in order to solve this system of equation we say that let

0.4x - 0.1y = 2 ... equation 1

0.2x + 0.5y = 1 ... equation 2

from equation 2

0.2x + 0.5y = 1 ... equation 2

0.2x = 1 - 0.5y

divide both sides by the coefficient of x which is 0.2

0.2x/0.2 = (1 - 0.5y) / 0.2

x = (1 - 0.5y) / 0.2 ... equation 3

substitute for equation 3 in equation 1

0.4x - 0.1y = 2 ... equation 1

0.4 (1 - 0.5y) / 0.2 - 0.1y = 2

0.4 - 0.2y/0.2 - 0.1y = 2

multiply through by 0.2

we have,

0.4 - 0.2y - 0.02y = 0.4

collect the like terms

0.4 - 0.4 = 0.2y + 0.02y

0 = 0.22y

divide both sides by the coefficient of y which is 0.22

0/0.22 = 0.22y/0.22

y = 0

put y = 0 into equation 3

x = (1 - 0.5y) / 0.2 ... equation 3

x = 1 - 0.5 (0) / 0.2

x = 1 - 0/0.2

x = 1/0.2

x = 5

therefore the value of x is 5 and y is 0 respectively