If f (x) = 2x, then f '' (x) =

f'' (x) = 0

Step-by-step explanation:

f '' (x) is second derivative of f (x)

derivative of x ^n = n x^ (n-1)

derivative of constant = 0

so f'' (x) is derivative of derivative

f' (x) = 2 * 1 * x^ (1-1) = 2

f'' (x) = 0