The equation for a circle with center (h, k) is (x - h) ^2 + (y - k) ^2 = r^2. If a circle is modeled by the equation x^2 + (y + 6) ^2 = 100, what is the center of the circle?

Question

Mathematics

Franco

19 December, 00:59

The equation for a circle with center (h, k) is (x - h) ^2 + (y - k) ^2 = r^2. If a circle is modeled by the equation x^2 + (y + 6) ^2 = 100, what is the center of the circle?

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Lisa Petty · Answer 1

(x - h) ^2 + (y - k) ^2 = r^2

x^2 + (y + 6) ^2 = 100

we can rewrite this as

(x-0) ^2 + (y - - 6) ^2 = 10^2

the center is (0,-6) and the radius is 10