Which statement is true of x2 + 8x - 6?

0 (x - 2) is a factor of the polynomial.

(x + 2) is a factor of pe polynomial.

(x - 4) is a factor of the polynomial.

The polynomial is prime.

Let f (x) be x^2+8x-6

x-2=0

x=2

f (2) = (2) ^2+8 (2) - 6

= 4+16-6

= 20-6

= 14

(x-2) is not a factor of f (x).

x+2=0

x=-2

f (-2) = (-2) ^2+8 (-2) - 6

= 4-16-6

= - 18

(x+2) is not a factor of f (x).

x-4=0

x=4

f (4) = (4) ^2+8 (4) - 6

= 16+32-6

= 10+32

= 42

(x-4) is not a factor of f (x).

Since none of the given factors are the factors of f (x), and the question states that one of the statements given above are true, the true statement is that the polynomial is prime.

x+2 and X-4 are the factors