How many solutions does this quadratic equation have?

6p^2-7p+5=0

No Real soultions

Step-by-step explanation:

solve by using the discriminant

b^2-4ac

(-7) ^2 - 4 x 6 x 5

= - 71

negative--->-71<0 no real solution

It has no real solution.

Step-by-step explanation:

6p^2 - 7p + 5 = 0

For this equation: a = 6, b = - 7, c = 5

6p^2 + - 7p + 5 = 0

Step 1: Use quadratic formula with a=6, b=-7, c=5.

p = - b ± √b^2 - 4ac/2a

p = - (-7) ± √ (-7) ^2 - 4 (6) (5) / 2 (6)

p = 7 ± √-71/12