Solve:

x + 9

x2 - 5x + 6

<0

(-∞,-9) U (2,3)

Step-by-step explanation:

(x+9) (x²-5x+6) < 0

x²-5x + 6

= x² - 3x - 2x + 6

= x (x-3) - 2 (x-3)

= (x-3) (x-2)

Substituting

(x+9) (x-2) (x-3)

For x < - 9

the term is negative

For x >-9 x<2

the term is positive

For x>2 x<3

the term is negative

For x>3

the term is positive

(x+9) (x-2) (x-3) < 0

(-∞,-9) U (2,3)