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24 October, 06:56

bill and julio are selling wrapping paper for a school fundraiser. customers can buy rolls of plain wrapping paper and rolls of shiny wrapping paper. bill sold 8 rolls of plain wrapping paper and 10 rolls of shiny wrapping paper for a total of $328. julio sold 9 rolls of plain wrapping paper and 2 rolls of shiny wrapping paper for a total of $184. find the cost each of one roll of plain wrapping paper and one roll of shiny wrapping paper

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  1. 24 October, 10:04
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    Plain rolls: $16

    Shinny rolls: $20

    Step-by-step explanation:

    So, we have 2 equations to start with, let p = plain rolls and s = shinny rolls:

    1) 8p + 10s = 328

    2) 9p + 2s = 184

    We need to isolate one variable, usually I go for the one with the lowest multiplicative ... so let's go for the '2s' and isolate the s from equation 2.

    2s = 184 - 9p

    3) s = (184 - 9p) / 2

    And let's place that s equivalent into the first equation:

    8p + 10 (184 - 9p) / 2 = 328

    8p + 5 (184 - 9p) = 328

    8p - 45p + 920 = 328

    -37p = - 592

    p = 16

    Then we go into any of the 3 equations to get the value of s. Let's take the 3rd equation, it will be simpler:

    s = (184 - 9p) / 2 = (184 - 9*16) / 2

    s = (184 - 144) / 2 = 40/2 = 20

    Then last step, we enter the values for s and p in one of the first equations to validate it. We haven't worked with first equation, so let's use that one:

    8p + 10s = 328

    8 (16) + 10 (20) = 328

    128 + 200 = 328

    328 = 328

    Confirmed!
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