Ask Question
9 June, 06:50

Extraneous solution q-6 = square root 27-2q

+5
Answers (1)
  1. 9 June, 07:57
    0
    q = 1, q = 9

    Step-by-step explanation:

    Equation: q - 6 = √ (27 - 2q)

    Exponents: (q - 6) ² = 27 - 2q

    Simplify: q² - 12q + 36 = 27 - 2q

    Subtract: q² - 10q + 9 = 0

    Two numbers: a + b = - 10, ab = 9 - -> a = - 1, b = - 9

    Substitute: q² - 1q - 9q + 9 = 0

    Simplify: (q - 1) (q - 9) = 0

    Solve: q - 1 = 0, q - 9 = 0 - -> q = 1, q = 9
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Extraneous solution q-6 = square root 27-2q ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers