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31 August, 00:23

How many real solutions does this system of equations have? X^2 + 3 = y

3x-y+1 = 0

Answer choices:

A. 2

B. 1

C. 0

D. 3

+3
Answers (1)
  1. 31 August, 02:55
    0
    A

    Step-by-step explanation:

    x^2+3=y

    3x-y+1=0

    3x+1=y

    so x²+3=3x+1

    x²-3x+2=0

    x²-x-2x+2=0

    x (x-1) - 2 (x-1) = 0

    (x-1) (x-2) = 0

    x=1,2

    two solutions
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