What is the equation of the circle that has center (0,-8) and passes through (9,7) ?

Answer: x² + y² + 16y - 242 = 0

Step-by-step explanation: The equation of circle is given in the form (x - a) ² + (y - b) ² = r², where (a, b) is the center of the circle and r is the radius. But r is the distance from (0,-8) to (9,7)

the equation is (x-0) ² + (y + 8) ² = r²

x² + (y + 8) ² = r²

hence r² = (x₁ - x₂) ² + (y₁ - y₂) ²

r² = (0 - 9) ² + (-8 - 7) ² = 81 + 225 = 306

hence the equation is

x² + y²+16y+64 = 306

x² + y² + 16y - 242 = 0