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9 January, 02:22

Suppose you choose a tile at random from a bag containing 2 a's, 3 b, s, and 4c, s. You replace the first tile in the bag and the choose again. Find the probability p (a and b)

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  1. 9 January, 04:13
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    Answer:4/27

    Step-by-step explanation:

    P (B) = 3/9; P (C) = 4/9

    3 of the 9 tiles are B's and 4 out of 9 tiles are C's

    P (B and C) = P (B) x P (C)

    = 3/9 * 4/9 = 12/81 = 4/27
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