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11 June, 08:58

What is the slope of a line perpendicular to the line whose equation is 3x-12y=216

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  1. 11 June, 10:40
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    Step-by-step explanation:

    Here 3x-12y-216=0

    Reducing into slope intercept form

    -12y = - 3x + 216

    12y = 3x - 216

    Which is in the form of, y = mx + c

    Slope (m) = 3
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