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24 February, 16:45

Find the 64th term of the following arithmetic sequence.

17, 26, 35, 44, ...

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  1. 24 February, 20:16
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    take the difference

    26-17=9

    35-26=9

    the first term is 17

    and the nth term is 64

    use the formula

    tn=a + (n-1) d

    let a be 17

    let n be 64

    let d be 9

    then you substitute

    t64=17 + (64-1) 9

    =17 + (63) 9

    =17+567

    =584

    so the 64th term is 584.
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