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11 September, 09:18

A mountain bike tire completes 40 revolutions and travels 272 feet. Rounded to the nearest inch, what is the diameter of the bike's tire? Use 3.14 for pi.

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  1. 11 September, 10:41
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    26 inches

    Explanation:

    When the tire does not slip, each revolution means that the bike advance a distance equal to the circumference of the tire.

    Thus, when 40 revolutions are completed, the bike will advance a distance equal to 40 times the circumference of the bike:

    distance = 40 * circumference

    The circumference is equal to:

    circumference = 2π * radius

    Using π = 3.14:

    272 feet = 40 * 2 * 3.14 * radius

    radius = 1.0828 feet

    diameter = 2 * radius = 2.1656 feet

    Convert to inches: 1 feet = 12 inches:

    diameter = 2.1656 feet * 12 inches/feet = 25.9872 inches ≈ 26inches
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