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1 June, 18:45

Simplify: |x+3|, if x>2

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  1. 1 June, 19:56
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    I believe it would be 0 and up

    Step-by-step explanation:

    |x + 3|

    |3 + 3|

    3 - 3 = 0

    and X can be any number higher than two so it would go up by one each time. 0,1,2,3 etc ...
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