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8 May, 13:02

One number is seven less than five times another. If their sum is decreased by four the result is one. Find the numbers

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  1. 8 May, 14:23
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    Let the number be Y.

    Y is seven

    less than 5 times another (let that other be X)

    Y=7-5X

    sum of both Y and X minus 4 gives one

    Y+X-4=1

    now solve both equations.
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