Find the equation of a circle that has its center at (6,-4) and has a radius of 3.

(x-6) ^2 + (y+4) ^2 = 9

Step-by-step explanation:

The equation of a circle is given by

(x-h) ^2 + (y-k) ^2 = r^2 where (h, k) is the center and r is the radius

(x-6) ^2 + (y - - 4) ^2 = 3^2

(x-6) ^2 + (y+4) ^2 = 3^2

(x-6) ^2 + (y+4) ^2 = 9

I think it's 9 but not sure