Find the equation of a circle that has its center at (6,-4) and has a radius of 3.

Question

Mathematics

Cheyenne

9 December, 21:33

Find the equation of a circle that has its center at (6,-4) and has a radius of 3.

+3

Answers (2)

Know the Answer?

Ellie Bullock · Answer 1

(x-6) ^2 + (y+4) ^2 = 9

Step-by-step explanation:

The equation of a circle is given by

(x-h) ^2 + (y-k) ^2 = r^2 where (h, k) is the center and r is the radius

(x-6) ^2 + (y - - 4) ^2 = 3^2

(x-6) ^2 + (y+4) ^2 = 3^2

(x-6) ^2 + (y+4) ^2 = 9

Gabriella Lawson · Answer 2

Gabriella Lawson 9 December, 22:37

0

I think it's 9 but not sure