Evaluate the piecewise function below for f (0):

f (x) = { 5 if x < 0

x + 3 if 0 < = x < = 4

2x - 1 if x > 4

Write answer as a single number

Evaluate f (0)

We have 3 different function inside piecewise function

f (x) = 5 if x < 0

f (x) = x + 3 if 0 < = x < = 4

f (x) = 2x - 1 if x > 4

f (0) means we need to find f (x) when x=0

Now we check all the inequalities that satisfies x=0

0 < = x < = 4 means x = 0 to 4 but 4 is not included

x=0 satisfies the inequality 0 < = x < = 4

So we use f (x) = x + 3 to find f (0)

Replace x with 0

f (x) = x + 3

f (0) = 0 + 3 = 3

f (0) = 3