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24 February, 20:45

Multiply out 5x (2x-3y)

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Answers (2)
  1. 24 February, 23:25
    0
    You start by distributing the 5x, so that it's 5x (2x) and 5x (3y). That becomes 10x^2 and 15xy. Put it back, and it's 10x^2 - 15xy.
  2. 24 February, 23:49
    0
    Expand

    5x * 2x + 5x * - 3y

    Rake out the constants

    (5 * 2) x + 5x * - 3y

    Simplify 5 * 2 to 10

    10x + 5x * - 3y

    Use the product rule: x^ax^b = x^a + b

    10x^2 + 5x * - 3y

    Simplify 5x * - 3y to - 15xy

    = 10x^2 - 15xy
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