Ken paid 412 for two magazines. The cost of each magazine was multiple of 43. What are the possible prices of the magazines

25, 43, 68, 111, 154, 197, 240, 283, 326, 369.

412 - 43 = 369

412 - 86 = 326

and so on.

I'm guessing you mean magazines as in bullets. Well, if he paid $412 dollars for two, and each were sold as a multiple of 43. Then each bullet was $4.79.

You find this by dividing 412 by 2 which gives you $206.

Now divide that by 43. Which is $4.79 (. ea) bullet.