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9 September, 10:14

What are the binomial factors of the polynomial x^3-5x^2+2x+8

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Answers (2)
  1. 9 September, 12:13
    0
    (-x - 1) • (x - 2) • (x - 4)

    Step-by-step explanation:

    Step by step solution:

    Step 1:

    Equation at the end of step 1:

    (((0 - (x3)) + 5x2) - 2x) - 8

    Step 2:

    Step 3:

    Pulling out like terms:

    3.1 Pull out like factors:

    -x3 + 5x2 - 2x - 8 =

    -1 • (x3 - 5x2 + 2x + 8)

    Checking for a perfect cube:

    3.2 x3 - 5x2 + 2x + 8 is not a perfect cube

    Trying to factor by pulling out:

    3.3 Factoring: x3 - 5x2 + 2x + 8

    Thoughtfully split the expression at hand into groups, each group having two terms:

    Group 1: 2x + 8

    Group 2: x3 - 5x2

    Pull out from each group separately:

    Group 1: (x + 4) • (2)

    Group 2: (x - 5) • (x2)
  2. 9 September, 13:53
    0
    I think the answer is B on edge

    Step-by-step explanation:

    (x - 4), (x - 2), (x + 1)
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