What is the slope of a line perpendicular to the line whose equation is

10x-8y=-8010x-8y=-80

10x-8y=-80. Fully reduce your answer.

The slope of the other line is - 4/5

Step-by-step explanation:

In this question, we are asked to calculate the slope of a line which is perpendicular to the line;

10x - 8y = - 80

The first thing to do here is to write the equation in the standard form for a linear equation.

The standard form is y = mx + c where m refers to the slope and c refers to the y-intercept

Rewriting the equation we have;

8y-80 = 10x

8y = 10x + 80

Now divide the through by 8

We have;

y = 10x/8 + 10

Thus, comparing with y = mx + c, our m here is 10/8

Now for the two lines to be perpendicular, the product of their slope would be equals to - 1

Let's say the slopes are m1 and m2

mathematically m1m2 = - 1

since m1 = 10/8

10m2/8 = - 1

m2 = - 8/10

m2 = - 4/5