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6 November, 16:46

The equation for a circle is (x-2) 2 + (y+3) 2=9, what is the center of the circle?

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  1. 6 November, 18:34
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    (2, - 3)

    Step-by-step explanation:

    Compare the given (x-2) 2 + (y+3) 2=9 to the standard equation

    (x - h) ^2 + (y - k) ^2 = r^2.

    It becomes obvious that h = 2, k = - 3 and r = 3.

    The center of this circle is (h, k) : (2, - 3).
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