The equation for a circle is (x-2) 2 + (y+3) 2=9, what is the center of the circle?

(2, - 3)

Step-by-step explanation:

Compare the given (x-2) 2 + (y+3) 2=9 to the standard equation

(x - h) ^2 + (y - k) ^2 = r^2.

It becomes obvious that h = 2, k = - 3 and r = 3.

The center of this circle is (h, k) : (2, - 3).