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14 February, 21:43

For three consecutive numbers, the sum of the first number, twice the second, and 7

less than the third is 133. What are the three numbers?

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Answers (1)
  1. 14 February, 23:35
    0
    a = 34

    b = 34

    c = 36

    Step-by-step explanation:

    a; b; c = consecutive numbers = >

    b = a + 1

    c = a + 2

    a + 2b + c - 7 = 133

    a + 2 (a + 1) + (a + 2) - 7 = 133

    a + 2a + 2 + a + 2 - 7 = 133

    4a = 133 + 7 - 4

    4a = 136

    a = 34

    b = 34

    c = 36
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