Find a indicated real nth root (s) a.

n=9, a=-512

The root is = ?

We know that 512=2^9, which implies that (-2) ^9=-512 (since 9 is odd). Thus - 2 is one of the 9th root of - 512.

There are 8 (or 4 pairs of) other roots that are excluded because they are complex.

Therefore - 2 is the only real 9th root of - 512.