Harsh is part of a school cricket team, and this year he has scored and average of 46 runs. He has played 5 innings so far and his scores in 4 of them are 46,45, 39,55. What was his score on the last one?

Answer: his score on the last one is 45.

Step-by-step explanation:

Let h represent the his score on the last inning.

Average number of runs = sum of runs/total number of innings played.

From the information given,

Average number of runs = 46

total number of innings played = 5

Sum of runs = 46 + 45 + 39 + 55 + h = 185 + h

Therefore,

46 = (185 + h) / 5

Cross multiplying by 5, it becomes

46 * 5 = 185 + h

230 = 185 + h

h = 230 - 185

h = 45

Answer: 45

Step-by-step explanation:

Harsh is part of a school cricket team, and he has scored an average of 46 runs in 5 innings. His scores in 4 of them are 46,45, 39, and 55. His fifth score is calculated as follows:

Since he made 5 innings and has an average of 46, the total scores will be:

= 46 * 5

= 230

Total of his first 4 scores will be:

= 46 + 45 + 39 + 55

= 185

5th score = 230 - 185

= 45