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27 July, 01:07

Find the 9th term of an arithmetic sequence that has a 4th term of 27 and a 5th term of 19

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  1. 27 July, 01:54
    0
    -13

    Step-by-step explanation:

    5th term - 4th term = common difference

    = 19 - 27

    = - 8

    Thus the 9th term = 5th term + 4 (-8)

    = 19 - 32

    = - 13 (answer
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