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11 September, 12:48

Find the indicated values, where g (t) = t²-t and f (x) = 1+x.

f (2g (1))

A 1

B 3

C 30

D - 1

+4
Answers (2)
  1. 11 September, 14:19
    0
    Step-by-step explanation:

    f (2g (1)) = f (2*0) because : g (1) = 1² - 1 = 0

    f (2g (1)) = f (0) = 1+0 = 1 ... answer : A) 1
  2. 11 September, 15:49
    0
    A

    Step-by-step explanation:

    given g (t) = t² - t and f (x) = 1 + x

    To evaluate f (2g (1), evaluate g (1), multiply by 2 and use this value to evaluate f (x)

    g (1) = 1² - 1 = 1 - 1 = 0 ⇒ 2g (1) = 2 * 0 = 0

    f (0) = 1 + 0 = 1 → A
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