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22 May, 08:43

Find the nth degree polynomial function with real coefficients satisfying the given conditions. n=3; - 2 and 2+3i are zeros; leading coefficient is 1.

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  1. 22 May, 08:51
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    f (x) = x^3 - 2x^2 + 5x + 26

    Step-by-step explanation:

    When p is a root, (x - p) is a factor.

    If the polynomial has real coefficients, its complex roots come in conjugate pairs. Then the linear factorization for the given roots is ...

    f (x) = (x + 2) (x - 2-3i) (x - 2+3i) = (x + 2) (x^2 - 4x + 13)

    f (x) = x^3 - 2x^2 + 5x + 26
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