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25 February, 04:25

Find one value of x that is a solution to the equation: (x^2-6) ^2=-3x^2+18

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  1. 25 February, 06:18
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    root 3 or root 6

    Step-by-step explanation:

    Let x^2 = y

    (y-6) ^2 = - 3y+18

    (y-6) (y-6) = - 3y+18

    y^2-6y-6y+36 = - 3y+18

    y^2-12y+36 = - 3y+18

    y^2-12y+3y+36-18 = 0

    y^2-9y+18 = 0

    y^2-6y-3y+18=0

    y (y-6) - 3 (y-6) = 0

    (y-3) or (y-6) = 0

    y-3 = 0 or y-6 = 0

    y = 3 or 6

    remember that y = x^2

    x^2 = 6

    x = root 6

    x^2 = 3

    x = root 3

    x = root 3 or root 6
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