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29 April, 16:48

A ball is hurled in the air such that its horizontal (x) and vertical (y) shifts are given by the functions x (t) = 20t and y (t) = 40t - 5t2, where x and y are in meters and the time t is in seconds. What is the ratio of y to x at time t = 5 seconds?

0.25

0.50

0.75

0.85

+4
Answers (1)
  1. 29 April, 17:46
    0
    x (t) = 20t

    y (t) = 40t - 5t^2

    Since we are only interested in comparing the two at time t = 5 seconds, we plug in 5 everywhere we see the variable t and then compare x and y

    x (5) = 20 (5) becomes x (5) = 100

    y (5) = 40 (5) - 5 (5) ^2 becomes y (5) = 200 - 125 and then y (5) = 75

    The ratio of y to x can be expressed as: y/x, so we can say the ratio is equal to 75/100 or 0.75

    Answer: 0.75
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