Three consecutive integers have a sum of 42. Find the integers.

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The three integers are 13,14,15

Step-by-step explanation:

Let x be the first integer

x+1 be the second integer

x+2 be the third integer

The sum of the three integers is 42

x + (x+1) + (x+2) = 42

Combine like terms

3x+3 = 42

Subtract 3 from each side

3x+3-3 = 42-3

3x = 39

Divide by 3

3x/3 = 39/3

x = 13

x+1 = 14

x+2 = 15

The three integers are 13,14,15