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19 September, 22:43

Write a quadratic equation with the root of 1/3 and - 7/2

A-y = (x-3) (7x+2)

C-y = (3x-1) (2x+7)

D-y = (3x+1) (2x-7)

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Answers (2)
  1. 20 September, 01:12
    0
    The answer is C-y = (3x-1) (7x+2)
  2. 20 September, 01:14
    0
    C y = (3x - 1) (2x + 7).

    Step-by-step explanation:

    That would be y = (3x - 1) (2x + 7).

    if we solve (3x - 1) (2x + 7) = 0

    (3x - 1) (2x + 7) = 0

    3x - 1 = 0 or 2x + 7 = 0

    x = 1/3, - 7/2.
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