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Mathematics
Winnie
12 May, 22:41
Find the sum. 0+3+6 + ... + (3n-3)
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Danny Yoder
13 May, 01:59
0
Step-by-step explanation:
a1 = 0
an = a1 + (n - 1) * d = 3n - 3
a1 = 0
(n - 1) * d = 3 (n-1)
From which d = 3
Now for the sum
Sum = (a1 + an) * n/2
Sum = (an * n) / 2
Sum = 3 (n - 1) * n / 2
Sum = (3n - 3) * n/2
Sum = (3n^2 - 3n) / 2
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