Question 7

Algebraically solve for x:

-3x+3+12 = x6-12

3x+15=6x-12

2 Add

3

x

3x to both sides.

1

5

=

6

x

-

1

2

+

3

x

15=6x-12+3x

3 Simplify

6

x

-

1

2

+

3

x

6x-12+3x to

9

x

-

1

2

9x-12.

1

5

=

9

x

-

1

2

15=9x-12

4 Add

1

2

12 to both sides.

1

5

+

1

2

=

9

x

15+12=9x

5 Simplify

1

5

+

1

2

15+12 to

2

7

27.

2

7

=

9

x

27=9x

6 Divide both sides by

9

9.

2

7

9

=

x

9



27

= x

7 Simplify

2

7

9

9



27

to

3

3.

3

=

x

3=x

8 Switch sides.

x

=

3

x=3