Ask Question
7 July, 01:48

What is the x coordinate of the center of a circle equation is x^2 + y^2 + 4x - 6y = b

+4
Answers (1)
  1. 7 July, 03:36
    0
    x = - 2

    Step-by-step explanation:

    The equation of a circle in standard form is

    (x - h) ² + (y - k) ² = r²

    where (h, k) are the coordinates of the centre and r is the radius

    To obtain this form use the method of completing the square

    Given

    x² + y² + 4x - 6y = b (collect x and y terms together)

    x² + 4x + y² - 6y = b

    add (half the coefficient of x / y terms) ² to both sides

    x² + 2 (2) x + 4 + y² + 2 ( - 3) y + 9 = b + 4 + 9

    (x + 2) ² + (y - 3) ² = b + 13 ← in standard form

    with (h, k) = ( - 2, 3)

    Thus x - coordinate of centre is x = - 2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the x coordinate of the center of a circle equation is x^2 + y^2 + 4x - 6y = b ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers