F (x) = (x - 6) ^2 (x + 2) ^2

How many roots?

Question

Mathematics

Belen Stewart

11 March, 11:39

F (x) = (x - 6) ^2 (x + 2) ^2

How many roots?

+3

Answers (1)

Know the Answer?

Rodney Harrington · Answer 1

Two double roots in this case.

I could say 4, but you have a pair of double roots x = 6 and x = - 2

Step-by-step explanation:

x = 6 is a double root of f (x)

x = - 2 is a double root of f (x)

F (x) = (x - 6) ^2 (x + 2) ^2How many roots?

F (x) = (x - 6) ^2 (x + 2) ^2

How many roots?